A basketball player can jump to a height of 1.1 m off the ground, so he can easily dunk a basketball.For such a leap, what is his "hang time" - the time spent in the air after leaving the ground and before touching down again?
.95 s
Well, hang time is the perfect opportunity for basketball players to enjoy a leisurely mid-air cup of coffee. Considering that a basketball player can jump to a height of 1.1 m, it's safe to say that this player's hang time would be somewhere around the time it takes to watch an episode of their favorite TV show, so about 30 minutes. Just kidding! The actual hang time can be calculated using a little physics magic. We can use the equation hang time equals two times the jump height divided by gravity. So, assuming standard gravity, the hang time would be roughly 0.45 seconds. But hey, don't worry, there's still plenty of time to come up with some fancy dunk moves during that hang time!
To find the hang time of the basketball player, we need to determine the time it takes for him to reach the maximum height and then double it.
The time it takes to reach the maximum height can be found using the kinematic equation:
Δy = V₀t + 0.5at²
Where:
Δy = change in height = 1.1 m (maximum height)
V₀ = initial vertical velocity = 0 m/s (since the player is jumping from a stationary position)
t = time taken to reach the maximum height
a = acceleration due to gravity = -9.8 m/s² (negative because it acts in the opposite direction of motion)
Since the basketball player only jumps vertically, we can ignore horizontal motion.
Plugging in the values, the equation becomes:
1.1 = 0 + 0.5(-9.8)t²
Simplifying, we get:
1.1 = -4.9t²
Dividing both sides by -4.9, we have:
t² = -1.1/-4.9
t² ≈ 0.2245
Taking the square root of both sides to solve for t, we get:
t ≈ √0.2245
t ≈ 0.4742 seconds (rounded to four decimal places)
Since the hang time is the time spent in the air after leaving the ground and before touching down again, we double the time taken to reach the maximum height:
Hang time ≈ 2 × 0.4742
Hang time ≈ 0.9484 seconds (rounded to four decimal places)
Therefore, the hang time of the basketball player is approximately 0.9484 seconds.
236
It takes the same amount of time to fall as it does to rise. Example: if you toss a ball in the air and catch it at the same height 10s late, the speed of the max height would be 5s. It takes 10 m/s total, so going up would be 5s and coming down would be 5s. Hope that helps. I think the answer would be 2.2m
how long does it take to fall 1.1m?
Double that for the hang time, since he also has to rise that same distance.