A penny is dropped from the top of Bank of America building. How long does it take to reach the group? Assume the back is 1024 ft high.

My work so far:
-16t^2+0t+1024
t=8 sec
Is this correct? Thanks!

looks good to me.

To determine how long it takes for the penny to reach the ground, you can use the equation of motion:

h(t) = -16t^2 + vt + h0

Where:
h(t) is the height of the penny at time t
v is the initial velocity of the penny (which is 0 since it is dropped)
h0 is the initial height of the penny (1024 ft)

Substituting the given values into the equation, we have:

h(t) = -16t^2 + 0t + 1024

To find the time it takes for the penny to reach the ground, we need to solve for t when h(t) = 0:

0 = -16t^2 + 1024

Now, let's solve this equation for t:

-16t^2 + 1024 = 0
Divide both sides by -16 to simplify the equation:
t^2 - 64 = 0
Factor the equation:
(t + 8)(t - 8) = 0

From this equation, we have two possible solutions:
t + 8 = 0 or t - 8 = 0

Solving for t in each case:

1. t + 8 = 0
t = -8 (This is not possible, as time cannot be negative in this case.)

2. t - 8 = 0
t = 8

Therefore, the penny takes 8 seconds to reach the ground from the top of the Bank of America building. Your calculation of t = 8 seconds is correct.