what is the difference between line p (-4, 3) and q (6, 1)? round to the nearest tenth. This is practice please help!

those two quantities are points, not lines.

the only difference between them is their location.

I think you want the distance between the points. That is, the length of the line segment joining them.

That would be

√((6-(-4))^2+(1-3)^2) = √(10^2+2^2) = √104 = 10.2

Just simplify that for your answer

To find the difference between two points on a coordinate plane, you need to calculate the distance between those points using the distance formula.

The distance formula is given by:

d = √[(x2 - x1)^2 + (y2 - y1)^2]

Where (x1, y1) and (x2, y2) are the coordinate points.

Let's apply this formula to find the difference between point P(-4, 3) and point Q(6, 1).

We can substitute the given coordinates into the formula:

d = √[(6 - (-4))^2 + (1 - 3)^2]
= √[(10)^2 + (-2)^2]
= √[100 + 4]
= √104

Now, rounding to the nearest tenth, we get:

d ≈ 10.2

Therefore, the difference between line P(-4, 3) and Q(6, 1) is approximately 10.2 units.