A 600 meters long train travels through a 4200 meter tunnel. Two full minutes elapsed from time the front of the train enters the tunnel until the last wagon exits the tunnel. What is the speed, in meters per second, of the train?
The tunnel is 7 trains long. So, 8 train lengths must pass through the tunnel in 2 minutes. The speed is thus
8(600m)/(120s) = 40 m/s
Ty steve
To find the speed of the train in meters per second, we need to know the total distance traveled by the train and the time it took. In this case, we have the distance of the tunnel and the time it took for the train to pass through.
First, let's calculate the time it took for the train to pass through the tunnel. We are given that two full minutes elapsed from the time the front of the train entered the tunnel until the last wagon exited the tunnel. One minute is equivalent to 60 seconds, so two minutes would be 120 seconds.
Next, we need to calculate the total distance traveled by the train. The train enters the tunnel when the front of the train enters and exits the tunnel when the last wagon exits. So, the total distance traveled by the train is the length of the train plus the length of the tunnel.
Total distance traveled by the train = Length of train + Length of tunnel
Total distance traveled by the train = 600 meters + 4200 meters
Total distance traveled by the train = 4800 meters
Now, we can calculate the speed of the train using the formula:
Speed = Distance / Time
Speed = 4800 meters / 120 seconds
Speed = 40 meters per second
Therefore, the speed of the train is 40 meters per second.