12.) Chlorine reacts with potassium bromide to produce potassium chloride and bromine.

a.) write a chemical equation, using words, to represent the above chemical reaction.

Answer: Chlorine + potassium bromide ==> potassium chloride + bromine
(Is this correct?)

b) Suppose 4.0 g of chlorine completely reacts with 13.4 g of potassium bromide producing 8.4 g of potassium chloride. What mass of bromide is produced?

Yes, #1 is right. To do #2, look at your equation and fill in the blanks but I will use symbols to save space.

Cl2 + 2KBr ==> 2KCl + Br2
4.0...13.4.....8.4.....x
Remember the Law of conservation of mass; i.e., matter is not created or destroyed. Therefore, since you have 17.4 g on the left you must have 17.4 g on the right. You know KCl is 8.4 and remainder must be Br2.

Chlorine reacts with potassium bromide to produce potassium chlorideChlorine reacts with potassium bromide to produce potassium chloride . .Chlorine reacts with potassium bromide to produce potassium chloride .

a.) Yes, your chemical equation representation is correct: Chlorine + potassium bromide → potassium chloride + bromine.

b) To solve this problem, we need to use the concept of stoichiometry and the principle of conservation of mass.

First, we need to determine the molar masses of the substances involved:
- Chlorine (Cl2) has a molar mass of 35.45 g/mol.
- Potassium bromide (KBr) has a molar mass of 119 g/mol.
- Potassium chloride (KCl) has a molar mass of 74.55 g/mol.
- Bromine (Br2) has a molar mass of 159.8 g/mol.

Next, we need to find the moles of chlorine, potassium bromide, and potassium chloride using their respective masses:
- Moles of chlorine = mass (g) / molar mass (g/mol) = 4.0 g / 35.45 g/mol = 0.113 mol
- Moles of potassium bromide = mass (g) / molar mass (g/mol) = 13.4 g / 119 g/mol = 0.112 mol
- Moles of potassium chloride = mass (g) / molar mass (g/mol) = 8.4 g / 74.55 g/mol = 0.113 mol

From the balanced chemical equation, we can see that the mole ratio between chlorine and potassium bromide is 1:1. Therefore, 0.113 mol of chlorine reacts with 0.113 mol of potassium bromide.

Since the reaction is assumed to go to completion, the limiting reactant is potassium bromide, and the number of moles of bromine produced is the same as the number of moles of potassium bromide: 0.112 mol.

Lastly, we can calculate the mass of bromine produced using its molar mass:
Mass of bromine = moles of bromine × molar mass of bromine
Mass of bromine = 0.112 mol × 159.8 g/mol = 17.9 g

Therefore, 17.9 grams of bromine are produced.

a) The correct chemical equation for the reaction is:

Chlorine + potassium bromide -> potassium chloride + bromine

b) To find the mass of bromide produced, we can follow these steps:

Step 1: Calculate the moles of each substance using their molar masses.
- Chlorine (Cl2): Molar mass = 2 * atomic mass of chlorine = 2 * 35.45 g/mol = 70.90 g/mol
- Potassium bromide (KBr): Molar mass = atomic mass of potassium + atomic mass of bromine = 39.10 g/mol + 79.90 g/mol = 119.00 g/mol
- Potassium chloride (KCl): Molar mass = atomic mass of potassium + atomic mass of chlorine = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol

Step 2: Determine the limiting reagent.
To find the limiting reagent, we compare the moles of chlorine and potassium bromide. Chlorine reacts with potassium bromide in a 1:2 molar ratio based on the balanced equation.
Moles of chlorine = mass of chlorine / molar mass of chlorine = 4.0 g / 70.90 g/mol ≈ 0.0562 mol
Moles of potassium bromide = mass of potassium bromide / molar mass of potassium bromide = 13.4 g / 119.00 g/mol ≈ 0.1126 mol

Since the molar ratio is 1:2, we see that the moles of chlorine are half of the moles of potassium bromide. Therefore, the chlorine is the limiting reagent.

Step 3: Calculate the moles of bromide produced.
From the balanced equation, we know that 1 mole of chlorine reacts with 2 moles of bromide to produce 1 mole of bromine. Therefore, the number of moles of bromide produced will be equal to the number of moles of chlorine used.

Moles of bromide = moles of chlorine = 0.0562 mol

Step 4: Calculate the mass of bromide produced.
Mass of bromide = moles of bromide * molar mass of bromide
Mass of bromide = 0.0562 mol * 119.00 g/mol ≈ 6.68 g

Therefore, the mass of bromide produced is approximately 6.68 g.