A particular brand of gasoline has a density of 0.737 g/mL at 25 ∘C. How many grams of this gasoline would fill a 13.2 gal tank (1US gal=3.78L)?

13.2 gal x (3.78 L/gal) = ?L

?L x (1000 mL/1 L) = ?
grams = volume x density. You know volume in mL and density in g/mL so you can calculate grams.

A particular brand of gasoline has a density of 0.737 g/mL at 25 ∘C. How many grams of this gasoline would fill a 12.9 gal tank (1US gal=3.78L)?

To find out how many grams of gasoline would fill the tank, we need to first convert the volume of the tank from gallons to milliliters, and then use the density to calculate the mass.

Step 1: Convert the volume of the tank from gallons to milliliters.
Given:
1 U.S. gallon = 3.78 L
1 L = 1000 mL

So, 1 U.S. gallon = 3.78 L = 3.78 * 1000 mL = 3780 mL

Step 2: Calculate the mass of gasoline using the density.
Given:
Density of gasoline = 0.737 g/mL
Volume of tank = 13.2 gal = 13.2 * 3780 mL (using the conversion from Step 1)

Mass = Volume * Density

Substituting the values:
Mass = 13.2 * 3780 mL * 0.737 g/mL

Calculating:
Mass = 37,512 g

Therefore, approximately 37,512 grams of gasoline would fill a 13.2-gallon tank.