On the Moon, the acceleration due to gravity is 1.62 m/s^2. How far would a 19 g rock fall from rest in 6.5 seconds if the only force acting on it was the gravitational force due to the Moon?
s(t) = 1/2 at^2
You have a, so plug it in. The mass does not matter.
35 m
the acceleration of gravity on the moon is 1.62m/s2. if a ball is dropped on the moon from a height of 1.50m. determine the time for the ball to fall to the surface of the moon
To find the distance the rock would fall on the Moon, we can use the equation of motion known as the "displacement equation":
d = (1/2) * g * t^2
where:
d is the distance
g is the acceleration due to gravity
t is the time
In this case, on the Moon, the acceleration due to gravity is given as 1.62 m/s^2, and the time is given as 6.5 seconds.
Plugging in these values into the equation, we get:
d = (1/2) * 1.62 m/s^2 * (6.5 s)^2
First, let's calculate the part within the parentheses:
(6.5 s)^2 = 42.25 s^2
Now, let's calculate the overall result:
d = (1/2) * 1.62 m/s^2 * 42.25 s^2
Next, perform the multiplication:
d = 0.81 m/s^2 * 42.25 s^2
Now, multiply the acceleration and the time squared:
d = 34.2225 m
Therefore, the rock would fall approximately 34.2225 meters on the Moon if the only force acting on it was the gravitational force due to the Moon.