A force of 480 N is applied to a stationary wooden box in one direction and an 920 N horizontal force is applied in the opposite direction. What additional force is necessary for the box to remain stationary?
Assuming zero friction, the additional force is the equilibrant.
We have a force of +480 N and -920 N.
The equilibrant is the negative of the vector sum, namely
-(480-920)=440 N, i.e. 440 N in the same direction as the 480N force.
If friction is present, some additional steps are required.
To determine the additional force necessary for the box to remain stationary, we need to find the net force acting on the box. The net force is the vector sum of all the applied forces.
Given:
Force 1 (F1) = 480 N (applied to the right direction)
Force 2 (F2) = 920 N (applied to the left direction)
To find the net force, we need to subtract the force applied in the opposite direction from the force applied in the same direction:
Net Force = F1 - F2
Net Force = 480 N - 920 N
Net Force = -440 N (since the direction of F2 is opposite to F1)
Therefore, an additional force of 440 N in the same direction as Force 1 is necessary for the box to remain stationary.
To find the additional force necessary for the box to remain stationary, we need to consider the net force acting on the box. The net force is the vector sum of all the forces acting on the box.
In this case, we have a force of 480 N applied in one direction and a force of 920 N applied in the opposite direction. Since the forces are in opposite directions, we subtract the smaller force from the larger force to find the net force.
Net force = 920 N - 480 N
= 440 N
Therefore, to keep the box stationary, an additional force of 440 N in the opposite direction is necessary.