4a=1-b

4a=2-b

To solve this system of equations, we can use the method of substitution. We will solve one equation for one variable, and then substitute that expression into the other equation.

Let's solve the first equation for "a":

4a = 1 - b

Dividing both sides of the equation by 4:

a = (1 - b) / 4

Now, substitute this expression for "a" into the second equation:

4a = 2 - b

4((1 - b) / 4) = 2 - b

Simplifying,

1 - b = 2 - b

In this case, we notice that "b" appears on both sides of the equation. This means that no matter what the value of "b" is, the equation will always be true. Therefore, we have infinitely many solutions for this system of equations.

Please note that this is a special case and not all systems of equations will have infinite solutions.