Precalc
posted by Josh .
How do you know what quadrant these two are in? I'm having a little trouble determining. Can someone check if my answers are correct for all and help me fix it to make it right.
10.) The point is on the xaxis and 12 units to the left of the yaxis.
My answer: (0, 12)
12.) y<5 = Quadrant 3
16.) xy<0 = Quadrant 1
26.) (3, 1) & (2,1)
Find distance.
My answer: 5
30.) the 3 points of the triangle they gave are (1,5), (5,2), & (1,2)
Find the length of each side of the right triangle & show that these lengths satisfy the pythagorean theorem.
??
42.) (1,2) & (5,4)
Distance answer= square root 40
midpoint= 2,3)
47.) (16.8, 12.3) & (5.6, 4.9)
Distance answer= square root 556.52 or 23.6
Midpoint= (5.6, 8.6)

Are These Right??
I'm kinda suck on #30!! 
10. Any point on the xaxis has a Y of 0;
12 units to the left of the Yaxis is an
X value ()12: P(12,0).
12. Q3, or Q4 depending on whether X is
positive or negative.
16. X,Y < 0. Q3.
26. (3,1), (2,1).
D^2 = X^2 + Y^2 = (2+3)^2 + (1+1)^2 =
25 + 0 = 25.
D = 5.
30. (1,5), (5,2), (1,2).
First, sketch the triangle showing the
given points.
The vertical side: (1,5), (1,2).
L^2 = X^2 + Y^2 = (11)^2 + (25)^2 =
0 + 49 = 49.
L = 7. or 5(2) = 5 + 2 = 7.
Horizontal side: (1,2), (5,2).
L = 51 = 4.
Hyp : (1,5), (5,2).
L^2 = (51)^2 + (25)^2 =
Use the length of the hor. and ver. sides to calculate length of hyp.
L^2 = X^2 + Y^2 .
42. (1,2),(x,y), (5,4).
D^2 = (5+1)^2 + (42)^2
Midpoint:
(5+1) = 2(x+1).
Solve for X.
(42) = 2(y2).
Solve for Y.
47. Same procedure as #42.
Respond to this Question
Similar Questions

Calculus
I asked for help on a question yesterday and I got really good help and I was wondering if someone could help with this problem too. This is the question: Find an equation of the line through the point (1,3) that cuts off the least … 
Potential Energy Q
Q A rollercoaster of mass 400 kg is stationary at the highest point on the track. It then drops to the lowest point through a vertical distance of 24 m. Calculate: a) the potential energy of the car at the top of the ride. b) the speed … 
Algebra
I am having trouble with this problem. I have done it several times and come up with two different answers. Can someone tell me what I am doing wrong? 
Math
Can someone please check my answers below for accurateness? 
Algebra
Hi, could someone possibly check my answers to these algebra questions? 
Math
Is this right? If you interchange the coordinates of any point in quadrant II, the new point would then be in (what Quadrant) Answer is quadrant IV. 
VERY URGENT MATH!!!
1. 3w – 10w (1 point) 13w –7w –7 7w 2. y + 2y +3z (1 point) 2y + 3z 3y + 3z 2y2 + 3z 6yz 3. 6r + r – 5r (1 point) 2r 1r + r 0r 7r – 5r 4. 5x + 2(x + 6) (1 point) 7x + 6 7x2 + 12 7x + 12 7x (x + 6) 5. –3m + 3(m + 6) (1 point) … 
MATH REPOST
Consider that point A is located at (x, y) in Quadrant I of the coordinate plane. In which quadrant is point B with coordinates (x, y) located? 
MATH! Help sooo confused!
Consider that point A is located at (x, y) in Quadrant I of the coordinate plane. In which quadrant is point B with coordinates (x, y) located A)Quadrant I B) Quadrant II C) Quadrant III D) Quadrant IV How do I even find this out? 
Ed Tech plz helppppp
What does it mean to troubleshoot your computer?