The height of a certain waterfall is 33.2 m. When the water reaches the

bottom of the falls, its speed is 25.8 m/s. Neglecting air resistance, what is
the speed of the water at the top of the falls?

The speed is horizontal at the top, call it u

and
it remains u all the way down because there is no horizontal force (acceleration).

So we have a vertical problem first.

v = g t
h = (1/2) g t^2
so
33.2 = 4.9 t^2
t^2 = 6.77
t = 2.60 seconds

so v = 9.81 * 2.6 = 25.5 m/s down

speed = s = 25.8 = sqrt(u^2 + 25.5^2)
u^2 + 652 = 666
u^2 = 13.64
u = 3.69 m/s

To determine the speed of the water at the top of the falls, we can use the principle of conservation of energy. According to this principle, the total mechanical energy (potential energy + kinetic energy) of an object remains constant in the absence of external forces like air resistance.

In this case, the potential energy of the water at the top of the falls is converted into kinetic energy when it reaches the bottom. The equation for potential energy is given by:

Potential Energy = mass * gravitational acceleration * height

To find the mass of the water, we can use the equation:

mass = density * volume

The density of water is approximately 1000 kg/m³. The volume of water can be calculated using the formula:

volume = area * height

Assuming the area of the waterfall is constant, we can solve for the volume. Since the area is not given in the question, we will assume it to be 1 m² for simplicity.

Now, we can substitute the values into the equations. The potential energy at the top of the falls is converted into kinetic energy at the bottom:

Potential Energy = Kinetic Energy

mass * gravitational acceleration * height = 0.5 * mass * velocity²

Simplifying the equation:

gravitational acceleration * height = 0.5 * velocity²

Since gravitational acceleration is approximately 9.8 m/s² and the height is given as 33.2 m, we can substitute these values:

9.8 * 33.2 = 0.5 * velocity²

Solving for velocity:

velocity² = (9.8 * 33.2) / 0.5

velocity ≈ √(320.16)

velocity ≈ 17.9 m/s

Therefore, the speed of the water at the top of the falls is approximately 17.9 m/s.