A 2000-kg car starts from rest and gains a velocity of 20 m/s in 5 /0s. What force was applied on it?
What formula/s will I use?!
To find the force applied on the car, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
The formula for force is:
Force (F) = mass (m) x acceleration (a)
In this case, the mass of the car is given as 2000 kg, and we need to find the acceleration. We can calculate the acceleration using the formula:
Acceleration (a) = (final velocity - initial velocity) / time
Given that the final velocity (v) is 20 m/s, the initial velocity (u) is 0 m/s, and the time (t) is 5 seconds, we can substitute these values into the formula to find the acceleration.
Acceleration (a) = (20 m/s - 0 m/s) / 5 s
Acceleration (a) = 20 m/s / 5 s
Acceleration (a) = 4 m/s^2
Now that we know the mass of the car (m = 2000 kg) and the acceleration (a = 4 m/s^2), we can substitute these values into the formula for force to find the answer:
Force (F) = mass (m) x acceleration (a)
Force (F) = 2000 kg x 4 m/s^2
Force (F) = 8000 N
Therefore, the force applied on the car is 8000 Newtons.
a = (V-Vo)/t.
V = 2o m/s.
Vo = 0.
t = 5 s.
F = M*a.