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2=log2(4)
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i need help with these two homework problems
Use the Laws of Logarithms to combine the expression into a single logarithm log2 5
Top answer:
log2 [ 5*sqrt(x+1)/x^5 ] log2 (x^2+x-2) = 2 x^2 + x - 2 = 2^2 = 4 x^2 +x -6 = 0 (x-2)(x+3) = 0 x = 2
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solve the equation
log2(x+4)-log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2
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log2(x+4) + log4(x) = 2 log2(x+4) + log2(x)/log2(4) = 2 log2(x+4) + log2(x)/2 = 2 2 log2(x+4) +
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1.Use the laws of logarithms to express log2 (6) รขโฌโ log2 (3) + 2log2 (8)^1/2 as a single logarithm; then evaluate.
2. For
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X2
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Solve:
2^(5x-6) = 7 My work: log^(5x-6) = log7 5x - 6(log2) = log7 5x = log7 + 6(log2) x = (log7 + log2^6) / 5 And textbook
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you are wrong and the textbook answer, the way you stated is, is wrong. 2^(5x-6) = 7 log[2^(5x-6)] =
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After simplification, the expression log2 3 โ 3 log2 ๐ฅ + 1/2 log2 (๐ฅ + 1) can be reduced to?
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Using logarithm properties, we can simplify the given expression as follows: log2 3 โ 3 log2 ๐ฅ
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Solve the equation log2 x + log2 (x + 4) - log2 (x - 2) = 4
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To solve the equation log2 x + log2 (x + 4) - log2 (x - 2) = 4, we can use the properties of
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Given that log2 3=h and log2 5=k, express log2 0.45 in terms of h and k.
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Dear Mandy, Here is the solution log2 0.45 = log2 (9/20) = log2 9 - log2 20 = 2log2 3 - log2 (4x5) =
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find the exact value of the following logarithm. Use the properties of logarithms show all work. log2 34-log2 17 (Those are
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log 2 (34/17) = log 2(2) which is 1 because 2^log2(2) = 2
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Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). For my answer, I got "All Real Numbers" or x=0 but I'm
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if course not "all reals" plug in just some value and see whether the equation balances. In
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Hi! Could someone possibly help me solve this?; log2(x+4)=log2(x^2+2). For my answer, I got "All Real Numbers" or x=0 but I'm
Top answer:
Log2(x+4) = Log2(x^2+2) x + 4 = x^2 + 2 x - x^2 = 2 - 4 -x^2 + x = -2 -x^2 + x + 2 = 0 Multiply both
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Can someone help solve this step by step
log2 4 + log2 (c-9) = 5
Solve for x if
I: Log2(xยฒ-2x+5)=2 ii: Log 3(xยฒ+2x+2)=0
Log2 (x-6) + log2 (x-4) - log2 X=2
log2โ36 - log2โ72
I am not sure how to do this question. I need an explanation.
Solve simultaneously the equations;
log2 ๐ฅ โ log2 ๐ฆ = โ1 and log๐ฆ(6๐ฅ + ๐ฆ) โ log๐ฆ(4๐ฅ โ ๐ฆ) = 1 A.
expand log2 (8x^2+48X+72)
log2+3log2-4log7
if log2 =0.301 than log20 =?
Without using tables or calculator solve for x in the equation. Log(2x-11)-Log2=Log3-Log2
Tell what the output value is for the function machine for the given values.
log 16.9=1.23 log2^152=9 log2^1=0 log0.046=1.34