a lottery game has balls numbered 1 through 19. What is the probability of selecting an even numbered ball or a 4?
Its hard one please anyone know how solve?
I got 10/19 but theres no cotrect one that shows it.
correct*
To solve this problem, we need to figure out the number of favorable outcomes and the total number of possible outcomes.
First, let's determine the number of favorable outcomes, which are the even numbered balls and the number 4.
There are a total of 19 balls. Out of these 19 balls, there are 9 even numbered balls (2, 4, 6, 8, 10, 12, 14, 16, and 18) and 1 ball numbered 4.
So the number of favorable outcomes is 9 + 1 = 10.
Next, we need to calculate the total number of possible outcomes, which are all the balls numbered 1 through 19.
Since there are 19 balls, the total number of possible outcomes is 19.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes.
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 10 / 19
Finally, we can simplify the fraction if needed. In this case, the fraction is already simplified, so the final probability is:
Probability ≈ 0.526 (rounded to three decimal places)
Therefore, the probability of selecting an even numbered ball or a 4 in this lottery game is approximately 0.526 or 52.6%.
how many even numbers are there? 9
So,
P(even) = 9/19
P(4) = 1/19
Now just add 'em up