on a town map ,each unit of the coordinate plane represents a mile. Three branches of a bank are located at A(-3,1) , and C (4,-1). A bank employee drives from branch A to branch B and then drives halfway to branch C before getting stuck in traffic. what is the minimum total distance the employee may have driven before getting stuck in traffic? round to the nearest tenth of a mile

7.6 Missing B.

4.5cm

9.7

7.1 the answer is 6.3 miles

To find the minimum total distance the bank employee may have driven before getting stuck in traffic, we need to calculate the distance between points A and C, and then divide it by 2.

Let's start by finding the distance between points A(-3,1) and C(4,-1):

- The horizontal distance between A and C is 4 - (-3) = 7 units (7 miles).
- The vertical distance between A and C is -1 - 1 = -2 units (-2 miles).

Using the Pythagorean theorem, we can calculate the distance between A and C:

Distance = √((horizontal distance)^2 + (vertical distance)^2)
Distance = √((7)^2 + (-2)^2)
Distance = √(49 + 4)
Distance = √53
Distance ≈ 7.28 miles (rounded to the nearest hundredth)

Now, we know that the bank employee drove halfway from A to C before getting stuck in traffic. Therefore, we need to find half of the calculated distance:

Half Distance = 7.28 miles ÷ 2
Half Distance ≈ 3.64 miles (rounded to the nearest tenth)

So, the minimum total distance the employee may have driven before getting stuck in traffic is approximately 3.64 miles.