Determine the standard form of the equation of the line that passes through (-6,6) and (3,-2).
My slope is -8/9
Y=mx+b
-2=-8/9(3) + b
SOLVING FOR b
-2=-24/9 + b
WHAT DO I DO NOW
the two-point form is
(y-y1) = (y2-y1)/(x2-x1) * (x-x1)
y-6 = (-2-6)/(3+6) (x+6)
y-6 = -8/9 (x+6)
9y-54 = -8x-48
The standard form is thus
8x+9y = 6