a block of mass 1500kg lying steady on horizontal surface of a table needs 200N horizontal force to come in motion. What is coefficient of static friction between the block and the surface of table
M*g = 1500 * 9.8 = 14,700 N. = Wt. of
block. = Normal(Fn).
Fap-Fs = M*a.
200-Fs = M*0 = 0.
Fs = 200 N.
Fs = u*Fn.
u = Fs/Fn = 200/14,700 = 0.0136.