a metre rule of length AB and mass 100g is suspended on a knife egde. if a mass of 200g is placed at 25cm mark from A at what point will another mass x be suspended from B?
200gX12.5cm=12.5cmXp.
p=200g
To find out at what point another mass should be suspended from point B, we can use the principle of moments.
The principle of moments states that for an object to be in equilibrium, the sum of the anticlockwise moments must be equal to the sum of the clockwise moments.
Let's calculate the moments:
The mass at point A creates a clockwise moment, while the unknown mass at point B creates an anticlockwise moment.
Moment at A = mass at A × distance from A
Clockwise Moment at A = 100g × 25cm = 2500 g.cm
To maintain equilibrium, the anticlockwise moment must balance the clockwise moment.
Moment at B = mass at B × distance from B
We need to find the distance from B, denoted as x, and the value of mass at B.
Since the metre rule is in equilibrium, the moments at A and B must balance each other:
2500 g.cm = mass at B × x
Given that the mass at B is 200g, we can substitute the values:
2500 g.cm = 200g × x
Now, let's calculate the distance from B, denoted as x:
x = (2500 g.cm) / (200g)
x = 12.5 cm
Therefore, another mass x should be suspended from point B at a distance of 12.5 cm from point B.