Subject physics a spring 20m long is streched to 25cm by a load of 50n ? What will be his length when strench to 100n assuming that the elastic limit is not reached
Mercy, if you look at the bottom of this page, where it says "Related Questions", this question has been answered about 3 different times.
Thank you Lori. That saves me some time.
NO
To determine the length of the spring when stretched to 100N, assuming the elastic limit is not reached, we can use Hooke's Law. Hooke's Law states that the force applied on a spring is directly proportional to the extension or compression of the spring, as long as the elastic limit is not exceeded.
Hooke's Law can be mathematically expressed as:
F = k * x
Where:
F is the force applied on the spring (in N),
k is the spring constant (in N/m), and
x is the extension or compression of the spring (in m).
In this case, we know that the spring is initially stretched from 20m to 25cm (or 0.25m) by a load of 50N. With this information, we can calculate the spring constant (k) using Hooke's Law:
50N = k * 0.25m
To solve for k, we divide both sides of the equation by 0.25m:
k = 50N / 0.25m
k = 200 N/m
Now that we have determined the spring constant (k), we can use Hooke's Law to find the length of the spring when stretched to 100N:
100N = 200 N/m * x
To solve for x, we divide both sides of the equation by 200 N/m:
x = 100N / 200 N/m
x = 0.5m
Therefore, the length of the spring when stretched to 100N, assuming the elastic limit is not reached, would be 0.5m.