chs
posted by peter .
Two wires support an electricity pole. if the wires make angles of 58°and 67° with the ground and AB=21m, calculate the lengths of the wires

Draw a diagram. If the pole has height h, then
h = 21/(cot58°cot67°) = 104.8
The two wires have length
104.8 csc67° = 113.9
104.8 csc58° = 123.6 
sorry steve you failed
All angles of a triangle add up to 180
degrees, so you have 2 angles you can
Find the third angle by 1805867=55
Now use the law of sines...(capital
is the angle and lower case the
side across from said angle
you have the 3 angles now and 1 side
use law of sines
a/sinA=b/sinB=c/sinC
(law of cos is for if you know sides
but not angles)
(law of tan if you know 3 of the 4
unknowns c^2=a^2+b^22abcos(C) )
well the top angle(C) is 55
which means AB would be across from
it being 21
so
a/sin58=b/sin67=21/sin55
so because c=21/sin55=
a=21/sin(55 deg)*sin(58 deg)
b=21/sin(55 deg)*sin(67 deg)
so
a = 21.7407868825
b = 23.5983076125
now just test this using tan
(remember bedmas order of operations)
2*21.7407868825*23.5983076125*cos(55 deg)
=588.541936444
=2*
21.7407868825^2+23.5983076125^2
=1029.541936444
1029.541936444588.541936444
=441
and 21^2 =.....drumroll please
441 on the nose!
and i have been out of school for 20 years
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Two wires support an electricity pole. if the wires make angles of 58°and 67° with the ground and AB=21m, calculate the lengths of the wires