A man gets a job with a salary of $40,000 a year. He is promised a $1900 raise each subsequent year. Find his total earnings for a 10-year period.

I got 59,000 and it is wrong what it the correct answer?

To find the correct answer, we need to calculate the man's salary each year and then sum up his total earnings over the 10-year period.

The initial salary is $40,000, and he gets a $1,900 raise each subsequent year. So, his salary for each year can be calculated as follows:

Year 1: $40,000
Year 2: $40,000 + $1,900
Year 3: $40,000 + $1,900 + $1,900
...

We can observe that the increase in salary is the same each year, so this is an arithmetic sequence. The formula to find the sum of an arithmetic sequence is given by:

Sum = (n/2) * (2a + (n-1)d)

where:
- n is the number of terms (in this case, 10 years)
- a is the first term (initial salary)
- d is the common difference (increase in salary each year)

Using the given values, we can plug them into the formula:

Sum = (10/2) * (2 * $40,000 + (10-1) * $1,900)

Simplifying this expression, we get:

Sum = 5 * ($80,000 + 9 * $1,900)
= 5 * ($80,000 + $17,100)
= 5 * $97,100
= $485,500

Therefore, the correct answer is that his total earnings for a 10-year period is $485,500.

To find the correct answer, we need to calculate the man's earnings for each year and then sum them up for the 10-year period.

The man's starting salary is $40,000, and he receives a raise of $1,900 each subsequent year. To calculate his earnings for each year, we start with his starting salary and add $1,900 for each additional year.

Year 1: $40,000
Year 2: $40,000 + $1,900 = $41,900
Year 3: $41,900 + $1,900 = $43,800
Year 4: $43,800 + $1,900 = $45,700
Year 5: $45,700 + $1,900 = $47,600
Year 6: $47,600 + $1,900 = $49,500
Year 7: $49,500 + $1,900 = $51,400
Year 8: $51,400 + $1,900 = $53,300
Year 9: $53,300 + $1,900 = $55,200
Year 10: $55,200 + $1,900 = $57,100

Now, we add up all his earnings for the 10-year period:

$40,000 + $41,900 + $43,800 + $45,700 + $47,600 + $49,500 + $51,400 + $53,300 + $55,200 + $57,100 = $505,300

Therefore, the correct answer is $505,300.

This is an arithmetic series where

a = 40000 , d=1900
you want sum(10)
sum(10) = (10/2)(2(40000) + 9(1900))
= 485500

What you found is how much he made in the 11th year.