calculus
posted by jean
a particle starts from rest and moves along a straight line with an acceleration equal to 2415√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return to the starting point?
help please thank you :)

bobpursley
d=0=1/2 a t^2=12t^27.5t^3/2
t^2(127.5sqrtt)=0
sqrtt=12/7.5
t= that squared.
check my thinking
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