I want to make 10 ml solution of 80% NaOH and 20% KOH
8 mL NaOH and 2 mL KOH
80% of 10 mL is 8
20% of 10 mL is 2
Do you want w/w or w/v %? I will assume w/v.
80% NaOH means 80g NaOH/100 mL solution.
20% KOH means 20 g KOH/100 mL solution.
You don't want 100 but only 10 so
80 g x 10/100 = 8 g NaOH
20 g x 10/100 = 2 g KOH
Weigh out 8 g NaOH and 2 g KOH, place in a 10 mL volumetric flask, add some water, swirl until all solid is dissolved, let the solution cool, then add H2O to the mark on the volumetric flask.
To make a 10 ml solution of 80% NaOH and 20% KOH, you will need to calculate the amount of each chemical required. Here's how you can do it:
Step 1: Determine the total amount of NaOH and KOH needed for the solution.
Since you are making a 10 ml solution, you need to calculate 80% of 10 ml for NaOH and 20% of 10 ml for KOH.
For NaOH:
Amount of NaOH = 80/100 x 10 ml
= 8 ml
For KOH:
Amount of KOH = 20/100 x 10 ml
= 2 ml
Step 2: Calculate the concentrations of NaOH and KOH in terms of volume.
To get the desired concentrations, divide the amount of each chemical by the total volume of the solution (10 ml).
Concentration of NaOH = (Amount of NaOH / Total volume of solution) x 100%
= (8 ml / 10 ml) x 100%
= 80%
Concentration of KOH = (Amount of KOH / Total volume of solution) x 100%
= (2 ml / 10 ml) x 100%
= 20%
Step 3: Prepare the solution.
In a laboratory, you can measure 8 ml of NaOH and 2 ml of KOH separately using a pipette or a measuring cylinder. Then, carefully pour both chemicals into a container and mix them well. This will give you a 10 ml solution consisting of 80% NaOH and 20% KOH.