Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Math
sin(arctan(-3pi/4))
1 answer
with some simple button-pushing on my calculator, I got
± .92052528
You can
ask a new question
or
answer this question
.
Related Questions
What values for theta(0 <= theta <= 2pi) satisfy the equation?
2 sin theta cos theta + sqrt 3 cos theta = 0 a. pi/2, 4pi/3,
Write z = 2(sqrt)2 + 2(sqrt)2i in polar form.
z = 4(sqrt)2 (cos pi/4 + i sin pi/4) z = 4 (cos pi/4 + i sin pi/4) z = 4 (cos 5pi/4
Find the area of the region bounded by the curves y = sin x, y = csc^2x, x = pi/4, and x = (3pi)/4.
The graph of a trigonometric function oscillates between y=1 and y=-7. It reaches its maximum at x= pi and its minimum at x=3pi.
Transform
arctan x + arctan y = pi/4 into algebraic expression A) x+xy-y = 1 B) x-xy-y = 1 C) x+xy+y = 1 D) x-xy+y = 1 Plsss help
Explain why sin^-1[sin(3pi/4)] does not = 3pi/4 when y=sin(x) and y=sin^-1(x) are inverses.
Any help on this question is greatly
What is the following limit?
lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim
Find the area bounded by the curves y=sin(4x) and y=0 for x between x=0 and x=3pi/8.
Please can you help me with this question?
Choose the option which is a false statement: A arctan(tan2/3pi))=-1/3pi B
Test for symmetry with repsect to Q=pi/2, the polar axis, and the pole.
r=16cos 3Q r=16cos(3pi/3 + 3h) = 16(cos3pi/2 3h- sin
