What is the probability of choosing an odd # from A that is AnB?
A{1,2,3,4,7,9}
B{3,7,9,11,12,15}
To find the probability of choosing an odd number from set A that is also in set B (A ∩ B), we need to determine the number of elements that satisfy this condition and divide it by the total number of elements in set A.
First, let's identify the odd numbers in set A: {1, 3, 7, 9}.
Now, let's find the numbers that are both in set A and set B: {3, 7, 9}.
So, there are three numbers in set A that are also in set B.
Next, let's determine the total number of elements in set A, which is 6.
Finally, to find the probability, we divide the number of desired outcomes (choosing an odd number from A that is also in B) by the total number of outcomes (total number of elements in A):
Probability = Number of desired outcomes / Total number of outcomes
= 3 / 6
= 1/2
= 0.5 (or 50%)
Therefore, the probability of choosing an odd number from set A that is in set B is 0.5 or 50%.