The air in a typical La Crosse basement contains 53 atoms of 222Rn per liter. A. If the basement has 950 ft^2 of floor space and is 8.0 feet tall, how many 222Rn atoms are there in the whole basement? B. Assuming a total pressure of 1.00 atm, what is the partial pressure of 222Rn at 19℃?

Could I get some help? I don't know how to do this

Sara, sam, et al. Why not use the same screen name?

volume room is 950 ft^2 x 8 ft = ? cubic feet. Convert to L.
You have 53 atoms Rn222/L so
53 atoms/L x #L = # Rn222 atoms in the basement.

B.
Convert # atoms Rn to mols Rn and use PV = nRT to solve for P.

DrBob is right and all but i just had a thought as i solved it about converting. I'd recommend converting feet to cm first since 1cm^3=1mL and that's a lot more convenient, easier to remember, and if you're in the middle of a test chances are its not gonna tell you how to convert a cubed foot into liters in the conversion charts. I really wish I had someone just giving me tips like this and that I hadn't had the need to suffer and go through bad experiences to think about these minor details.

Enrique is correct but just for the record this is how I did it.

7600 ft^3 x (1,728 in^3/ft^3) x (2.54 cm/in)^3 x (1 L/1000 cc) = ?
1,728 and 2.54 and 1000cc to 1L are just three of those conversion factors I memorized back in the days before calculators, computers, and such were in vogue.

Upon decomposition, one sample of magnesium fluoride produced 1.66 kg of magnesium and 2.57 kg of fluorine. A second sample produced 1.26 kg of magnesium

Of course, I can help you with that!

A. To calculate the number of 222Rn atoms in the entire basement, we need to know the volume of the basement. The volume can be calculated by multiplying the floor space by the height. Let's first convert the given measurements to a consistent unit:

1 ft = 0.3048 meters

Floor space = 950 ft^2 * (0.3048 m/ft)^2 = 88.2584 m^2
Height = 8.0 ft * 0.3048 m/ft = 2.4384 m

Now, the volume of the basement is calculated by multiplying the floor space by the height:

Volume = Floor space * Height = 88.2584 m^2 * 2.4384 m = 215.0275 m^3

Next, we need to convert the air concentration from liters to cubic meters:

Given air concentration = 53 atoms of 222Rn per liter
Air concentration in cubic meters = 53 atoms * (1 m^3 / 1000 L) = 0.053 atoms/m^3

Finally, we can calculate the total number of 222Rn atoms in the entire basement by multiplying the volume of the basement by the air concentration:

Number of 222Rn atoms = Volume * Air concentration
Number of 222Rn atoms = 215.0275 m^3 * 0.053 atoms/m^3

B. To calculate the partial pressure of 222Rn at 19℃, we can use the ideal gas law:

PV = nRT

Where:
P = Pressure (in atm)
V = Volume (in liters)
n = Number of moles
R = Ideal gas constant (0.0821 L × atm / K × mol)
T = Temperature (in Kelvin)

First, convert the temperature from Celsius to Kelvin:

19℃ + 273.15 = 292.15 K

Now, we can calculate the number of moles of 222Rn using the Avogadro's number (6.022 × 10^23 atoms per mole):

Number of moles of 222Rn = Number of atoms / Avogadro's number
Number of moles of 222Rn = Number of atoms / (6.022 × 10^23 atoms per mole)

Finally, we can substitute the values into the ideal gas law equation to calculate the partial pressure of 222Rn:

Pressure of 222Rn = (Number of moles / Volume) * R * Temperature

Please let me know if you need any further assistance!