# Math

posted by G

In a certain industry, 35% are female, 72% work full time and 18% are females who work full time.

Probability that a randomly chosen employee is female and does not work full time?
A: 0.18
B: 0.54
C: 0.11
D: 0.17
E: 0.098

I got 0.098 because I did 0.35 * 0.28. The actual answer is D. I cannot figure out how to get 0.17. Can you guide me how to get it? Or I might be correct and the answer is wrong

1. Anonymous

Imagine an industry with 100 employees.
35 of them are female. 18 of them work full time. So the rest works part time.

35 - 18 = 17

17/100 = 0.17

So, 0.17

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