Carbon tetracholoride is made according to the following reaction: carbon disulfide + chlorine gas yields carbon tetrachloride and disulfur dichloride. Write the correct balanced equation and then determine how many grams of CS2 are needed to make 16 kilograms of CCl4.
Ok so i got the balanced equation to be CS2 + 3Cl2 => CCl4 + S2Cl2
Then i got the mols for CCl4 to be 104.01 because i did 16000/153.62
Im completely lost after that
I responded at the original post. I was busy answered those million questions posted by Mindy so it took a little while to get back to your question.
To calculate the number of grams of CS2 needed to make 16 kilograms of CCl4, we can use stoichiometry.
First, let's calculate the molar mass of CS2:
Carbon (C) has a molar mass of 12.01 g/mol.
Sulfur (S) has a molar mass of 32.07 g/mol.
So, the molar mass of CS2 is 12.01 + (2 × 32.07) = 76.15 g/mol.
Now, let's set up the stoichiometric ratio between CS2 and CCl4 using the balanced equation:
CS2 + 3Cl2 → CCl4 + S2Cl2
From the equation, we can see that for every 1 mol of CS2, we produce 1 mol of CCl4.
Now, let's convert the mass of CCl4 (16 kilograms) into grams:
16 kilograms = 16,000 grams
Next, let's use the molar mass of CCl4 to convert grams to moles:
Molar mass of CCl4 = 12.01 × 4 + 35.45 × 4 = 153.82 g/mol
16,000 g ÷ 153.82 g/mol = 103.9 mol
Since the stoichiometric ratio between CS2 and CCl4 is 1:1, we know that we need 103.9 moles of CS2 to produce 103.9 moles of CCl4.
Finally, we can use the molar mass of CS2 to convert the number of moles to grams:
Molar mass of CS2 = 76.15 g/mol
103.9 mol × 76.15 g/mol = 7,918.9 grams
Therefore, approximately 7918.9 grams of CS2 are needed to make 16 kilograms of CCl4.