The roots of x^2-999999x-9999=0 and ? are additive intergers
A. x^2+999999x-9999=0
B. x^2-999999x+9999=0
C. x^2+999999x+9999=0
D. x^2-9999x-999999=0
To find the roots of the given quadratic equation x^2 - 999999x - 9999 = 0, we can use the quadratic formula. The quadratic formula states that given a quadratic equation in the form ax^2 + bx + c = 0, the roots can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, a = 1, b = -999999, and c = -9999. Plugging these values into the quadratic formula, we get:
x = (999999 ± √((-999999)^2 - 4(1)(-9999))) / (2*1)
Simplifying further, we have:
x = (999999 ± √(999999^2 + 39996)) / 2
Now, let's determine which answer choice also has roots that are additive integers.
A. x^2 + 999999x - 9999 = 0
B. x^2 - 999999x + 9999 = 0
C. x^2 + 999999x + 9999 = 0
D. x^2 - 9999x - 999999 = 0
Out of the provided answer choices, only option B has the same form as the original equation, with the signs flipped for the second and third terms. Taking the ± sign into account, we can confirm that the roots of the equation x^2 - 999999x + 9999 = 0 will also be additive integers.
Therefore, the correct answer is B: x^2 - 999999x + 9999 = 0.