Question

Can someone explain how

cos(X)/ square root (sin (X))

is 2 square root sin(x) +c

Thanks!

Answer 1

I assume you mean

∫ cos(x)/√(sinx) dx

let u^2 = sinx
2u du = cosx dx

Now the integral is

∫ 2u/u du = 2∫du
= 2u+c
= 2√(sinx)+c