Calculate the molarity of the solution:
42.6 g NaCl in 1.58 L
Na ---- 23 g/mol
Cl ---- 35.5 g/mol
so
NaCl 58.5 g/mol
so
42.6/58.5 = .728 mols
.728/1.58 = .461 mol/Liter
To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
Step 1: Convert the mass of NaCl into moles.
To do this, you need to divide the given mass of NaCl by its molar mass.
The molar mass of NaCl is:
Na (sodium) = 22.99 g/mol
Cl (chlorine) = 35.45 g/mol
Molar mass of NaCl = (22.99 g/mol + 35.45 g/mol) = 58.44 g/mol
Number of moles of NaCl = mass of NaCl / molar mass of NaCl
Number of moles of NaCl = 42.6 g / 58.44 g/mol = 0.729 mol
Step 2: Calculate the molarity.
Molarity (M) is defined as moles of solute (NaCl) per liter of solution (1.58 L).
Molarity (M) = moles of NaCl / volume of solution (in L)
Molarity (M) = 0.729 mol / 1.58 L ≈ 0.461 M
Therefore, the molarity of the solution containing 42.6 g NaCl in 1.58 L is approximately 0.461 M.
To calculate the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).
To get the amount of NaCl in moles, you can use the formula:
moles = mass / molar mass
The molar mass of NaCl is calculated by adding up the atomic masses of sodium (Na) and chlorine (Cl). The atomic mass of sodium is 22.99 g/mol, and the atomic mass of chlorine is 35.45 g/mol. Therefore, the molar mass of NaCl is 58.44 g/mol.
Substituting the given values, we have:
moles of NaCl = 42.6 g / 58.44 g/mol
Next, we need to convert the volume of the solution to liters:
1.58 L
Now, we can calculate the molarity by dividing the amount of NaCl in moles by the volume of the solution in liters:
molarity = moles / volume
Substituting the known values and performing the calculation, we have:
molarity = (42.6 g / 58.44 g/mol) / 1.58 L
molarity ≈ 0.491 M
Therefore, the molarity of the solution is approximately 0.491 M.