How much heat is required to raise the temperature of 100 g of lead 20 degrees C? The specific heat of lead is 0.0305 cal/g K.
A) 51 cal
B) 61 cal
C) 71 cal
D) 81 cal
The answer depends upon where the temperature is now. Assuming it is solid lead to solid lead (that is it does not go through a melting range or boiling range), it is
q = mass Pb x specific heat x 20
To calculate the amount of heat required to raise the temperature of a substance, we can use the formula:
Q = mcΔT
Where:
Q represents the heat required,
m represents the mass of the substance,
c represents the specific heat capacity of the substance,
ΔT represents the change in temperature.
Given:
Mass of lead (m) = 100 g
Change in temperature (ΔT) = 20 degrees C
Specific heat of lead (c) = 0.0305 cal/g K
Plugging in the values:
Q = (100 g) * (0.0305 cal/g K) * (20 degrees C)
Q = 61 cal
Thus, the amount of heat required to raise the temperature of 100 g of lead by 20 degrees C is 61 cal.
The correct answer is B) 61 cal.
To calculate the amount of heat required to raise the temperature of a substance, you can use the formula:
Q = m * c * ΔT
where:
Q is the heat energy (in calories)
m is the mass of the substance (in grams)
c is the specific heat of the substance (in cal/g K)
ΔT is the change in temperature (in degrees Celsius)
In this case, we want to find the amount of heat required to raise the temperature of 100 g of lead by 20 degrees Celsius. So, m = 100 g and ΔT = 20 °C. The specific heat of lead is given as 0.0305 cal/g K.
Plugging these values into the formula:
Q = 100 g * 0.0305 cal/g K * 20 °C
Q = 61 cal
Therefore, the amount of heat required to raise the temperature of 100 g of lead by 20 degrees Celsius is 61 calories.
So, the correct answer is B) 61 cal.