A picture hangs on the wall suspended by two strings, as shown in the

figure, with θ = 65°. The tension in string 1 is 1.3 N.
(a)Is the tension in string 2 greater than, less than, or equal to the tension in string 1? Explain.
(b) Verify your answer to part (a) by calculating the tension in string 2
(c) What is the weight of the picture?

See previous post: Sun, 7-12-15, 10:24 PM.

To answer these questions, we need to analyze the forces acting on the picture.

Let's start with part (a):

The tension in string 1 is given as 1.3 N. Since both strings are supporting the picture and the picture is at rest, the vertical forces must be balanced. This means that the tension in string 2 should be equal to the weight of the picture.

If the tension in string 2 is greater than 1.3 N, it would mean that the total upward force is larger than the downward force, which would result in an upward acceleration. Since the picture is at rest, this cannot be the case.

If the tension in string 2 is less than 1.3 N, it would mean that the total upward force is smaller than the downward force, which would result in a downward acceleration. Since the picture is at rest, this cannot be the case either.

Therefore, the tension in string 2 must be equal to the tension in string 1.

Now, let's move on to part (b) to verify our explanation:

Since the picture is at rest, the vertical forces must balance out. This implies that the tension in string 2 is also 1.3 N.

Thus, the tension in string 2 is equal to 1.3 N, confirming our initial explanation.

Finally, part (c):

To calculate the weight of the picture, we can use the following equation:

Weight = Mass * Gravitational acceleration

Since the problem does not provide the mass of the picture or the value of the gravitational acceleration, we cannot directly calculate the weight. However, if we were given these values, we could multiply them together to find the weight of the picture.