cant find much on how to solve problems like these. any help would be appreciated.
A pressure of 6000 Pa is exerted on a wall of 12 square meters area. What force is exerted on the wall?
What is the pressure at the bottom of a 50 m tall water tower?
What is the pressure at the bottom of a 50 m tall tank of Benzene? Density of Benzene is 0.90 g/cm3
A gold cylinder is suspended in water. Cylinder volume is 1 x 10-6 m3.
Density of gold is 19,300 kg/m3. What is the mass of the cylinder? What is the buoyancy force on the cylinder?
A rectangular block (0.25m x 0.50m x 1.00m) of brass is suspended in water. Density of brass is 8,600 kg/m3. What is the buoyancy force on the block? What is the mass of the block? What is the actual weight of the block? What is the apparent weight of the block when suspended in water?
A block of copper suspended in ethyl alcohol experiences a buoyancy force of 13 N. What is the volume of the block? Density of ethyl alcohol is 810 kg/m3.
6000 Pascals is 6000 Newtons per square meter.
Multiply that by the area of the wall in square meters to get the force in Newtons.
The density of water is about 1000 kg /m^3
so the weight of a cubic meter of water is about
m g = 1000 * 9.81 = 9810 Newtons
so a column of water 50 m high and one meter square across would weigh
50 * 9810 N
That force in ewtons presses down on your one square meter
so
we have 50 *9810 Newtons/ square meter
which is 50 * 9810 Pascals.
which is about
490,500 Pascals or about 5 atmospheres due to the water.
In fact you will have one atmosphere more due to the atmosphere itself but I suspect this means "gage pressure"
which is the pressure above atmospheric.
.9 g/cm^3 = 900 kg/m^3
so multiply the answer we got for the water tower by 0.90
10^-6 * 19300 = .0193 kg gold
mass of 10^-6 m^3 water = 10^-3 kg
buoyant force = weight of water displaced = 10^-3 kg * 9.81 = .00981 N
The last two are the same idea.
awesome, thanks
You are welcome.
4a. Mass = 1*10^-6m^3 * 19,300kg/m^3 =
0.0193 Kg .
4b. Fb = 1*10^-6m^3 * 1000Kg/m^3 = 0.001 Kg. = 0.0098 N.
5. V = 0.25 * 0.5 * 1 = 0.125 m^3.
a. Fb = 0.125m^3 * 1000Kg/m^3 = 125 kg.
= 1225 N.
b. M = 0.125m^3 * 8,600kg/m^3 =
c. = Wb = M*g Newtons.
6. V*D = 13 N.
V*810 = 13.
Solve for V.
Thank you Henry
Glad I could help.
To solve problems like these, we need to use the concepts of pressure, force, density, volume, and buoyancy.
1. Force exerted on a wall:
We use the formula: Force = Pressure × Area.
In this case, the pressure is given as 6000 Pa, and the area is given as 12 square meters.
Substituting these values into the formula, we get: Force = 6000 Pa × 12 m². Calculate the result to find the force exerted on the wall.
2. Pressure at the bottom of a water tower:
The pressure at a certain depth in a fluid is given by the formula: Pressure = Density × Gravitational Acceleration × Height.
In this case, the density of water is known (1000 kg/m³), the gravitational acceleration is known (9.8 m/s²), and the height is given as 50 m.
Substitute these values into the formula: Pressure = 1000 kg/m³ × 9.8 m/s² × 50 m. Calculate the result to find the pressure at the bottom of the water tower.
3. Pressure at the bottom of a tank of Benzene:
The formula is the same as in the previous question: Pressure = Density × Gravitational Acceleration × Height.
However, this time we need to consider the density of Benzene, which is given as 0.90 g/cm³. To use it in the formula, we need to convert it to kg/m³.
Multiply the density by 1000 to convert from g/cm³ to kg/m³: Density = 0.90 g/cm³ × 1000 kg/m³. Then substitute the values into the formula: Pressure = 0.90 kg/m³ × 9.8 m/s² × 50 m. Calculate the result to find the pressure at the bottom of the Benzene tank.
4. Mass of the gold cylinder and buoyancy force:
To find the mass of the gold cylinder, we use the formula: Mass = Volume × Density.
Substitute the given values: Mass = 1 x 10⁻⁶ m³ × 19,300 kg/m³. Calculate the result to find the mass of the cylinder.
To find the buoyancy force on the cylinder in water, we use Archimedes' principle: Buoyancy Force = Weight of Displaced Fluid.
The weight of the displaced fluid is equal to the weight of the fluid with the same volume as the submerged part of the cylinder.
In this case, the density of water is known (1000 kg/m³) and the volume of the submerged part of the cylinder is given (1 x 10⁻⁶ m³).
Multiply the volume by the density of water: Weight of Displaced Fluid = 1 x 10⁻⁶ m³ × 1000 kg/m³.
5. Buoyancy force, mass, actual weight, and apparent weight of a brass block:
To find the buoyancy force on the block in water, we use the same principle as before: Buoyancy Force = Weight of Displaced Fluid.
The density of water is 1000 kg/m³. The volume of the brass block is given as 0.25m × 0.50m × 1.00m.
Multiply the volume by the density of water: Weight of Displaced Fluid = (0.25m × 0.50m × 1.00m) × 1000 kg/m³.
To find the mass of the block, use the formula: Mass = Volume × Density. Substitute the given values.
To find the actual weight of the block, multiply its mass by the gravitational acceleration: Actual Weight = Mass × Gravitational Acceleration.
To find the apparent weight of the block in water, subtract the buoyancy force from the actual weight.
6. Volume of the copper block in ethyl alcohol:
Using the same principle as before, we have: Buoyancy Force = Weight of Displaced Fluid.
The density of ethyl alcohol is given as 810 kg/m³. The buoyancy force is given as 13 N.
Rearranging the formula, we can solve for volume: Volume = Buoyancy Force / (Density × Gravitational Acceleration).
Substitute the given values into the formula to find the volume.