Wendy is traveling 120 miles away from chasity. They are traveling towards each other. If chasity travels 4 mph faster than Wendy and they meet after 4 hours, how fast was each traveling?
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If Wendy's speed is w, their combined speed of approach is 2w+4
Since time = distance/speed, and they meet after 4 hours,
120/(2w+4) = 4
To solve this problem, we can use the formula:
Distance = Speed × Time
Let's assume that Wendy's speed is denoted by 'x' mph.
According to the question, Chasity travels 4 mph faster than Wendy. Therefore, Chasity's speed would be 'x + 4' mph.
Now let's analyze the information given:
Wendy travels 120 miles away from Chasity, so Wendy's distance would be 120 miles.
Since Wendy and Chasity are traveling towards each other, their combined distance would be equal to 120 miles.
We know that time is the same for both Wendy and Chasity, and they meet after 4 hours.
Applying the formula, the equation becomes:
Wendy's distance + Chasity's distance = Combined distance
120 miles + 4 hours × x mph + 4 hours × (x + 4) mph = 120 miles
Simplifying the equation:
120 miles + 4x mph + 16 mph + 16x mph = 120 miles
20x mph + 136 mph = 120 miles
Now we can simplify the equation further:
20x mph = 120 miles - 136 mph
20x mph = -16 mph
Divide both sides by 20:
x mph = -16 mph / 20
x mph = -0.8 mph
Uh-oh! It seems we encountered a problem with the math. The speed cannot be negative, so there might be an error in the question or the provided information.
Please double-check the question, or if you believe the provided information is correct, kindly provide additional context or clarify any uncertainties.