A town's population increased by 1200 people,and then this new population decreased 11%. The town now had 32 less people than it did before the 1200 increase. Find the original population.
Original=x
After first increase=x+1200
After decrease of 11%(11/100) remaining is 89%(89/100)
Towns population=89(x+1200)=x-32
=0.89x+1068=x-32
=x-0.89=1068+32
=11x/100=1100
=11x=11000
=X=10000
calculation is missing after the step
89X+1068 = X-32
it will be 88X + 1100 not 1100 =11X
original --- x
after first increase --- x + 1200
now decrease of 11%
-- 89% are left
.89(x+1200) = x-32
.89x + 1068 = x - 32
1100 = .11x
x = 10,000
If you think I answered correctly please help others
answer is 10000
10000
is it 10000
Let Population of town=x
After increase1200 i.e present population=x+1200
11℅ of present=(x+1200)11/100
11%decrease in present population=(x+1200)-(x+1200)11/100
As per problem
(x+1200)-(x+1200)11/100=x-32
100x+120000-11x-13200=100(x-32)
-11x=-110000
X=10000