A student mixes 764 mL of water and 476 mL of 1.00 x 10-5 M orange food dye solution. What is the concentration of this new dilute solution of orange food dye?
Sorry, figured it out.
1.00E-5 x [476/(1240)]= 3.84E-6
That's right, assuming that the volumes are additive. Technically they are not but at these concentrations one never would be able to measure the difference.
To find the concentration of the new dilute solution of orange food dye, we need to use the equation:
C1V1 = C2V2
Where C1 and V1 are the initial concentration and volume of the orange food dye solution, and C2 and V2 are the final concentration and volume of the diluted solution.
In this case, C1 is given as 1.00 x 10^-5 M, V1 is 476 mL, and V2 is the total volume of the final solution, which is given as the sum of both volumes of water and food dye solution, i.e., 764 mL + 476 mL = 1240 mL.
Now, let's plug these values into the equation:
(1.00 x 10^-5 M)(476 mL) = C2(1240 mL)
Simplifying:
C2 = (1.00 x 10^-5 M)(476 mL) / (1240 mL)
C2 = 4.61 x 10^-6 M
Therefore, the concentration of the new dilute solution of orange food dye is 4.61 x 10^-6 M.