When 6 boys were admitted and 6 girls left the %of boys increased from 60% to 75% . Find the original no. Of boys and girls in the clasa
b/(b+g) = 3/5
(b+6)/(b+6 + g-6) = 3/4
Originally, there were 24 boys and 16 girls.
24/(24+16) = 3/5
30/(30+10) = 3/4
To find the original number of boys and girls in the class, we can set up equations based on the given information.
Let's assume the original number of boys in the class is "B" and the original number of girls is "G."
According to the given information, when 6 boys were admitted, the total number of boys increased from 60% to 75%. This means that the ratio of boys to the total number of students changed from 60% to 75%.
Initially, the ratio of boys to the total number of students was 60%. Since the total number of students in the class is B + G, we can write this as:
(B / (B + G)) * 100 = 60
After 6 boys were admitted, the ratio of boys to the total number of students became 75%. Now, the total number of boys in the class is B + 6, and the total number of students is (B + 6) + G. So, we can write this equation as:
((B + 6) / ((B + 6) + G)) * 100 = 75
Now, we have two equations with two variables (B and G). We can solve these equations to find their values.
From the first equation, we get:
(B / (B + G)) * 100 = 60
B = 0.6(B + G)
From the second equation, we get:
((B + 6) / ((B + 6) + G)) * 100 = 75
Simplifying the second equation, we get:
(B + 6) = 0.75((B + 6) + G)
Now, we can substitute the value of B from the first equation into the second equation and solve for G:
0.6(B + G) + 6 = 0.75((B + 6) + G)
Simplifying and solving this equation will give us the value of G, the original number of girls in the class. Once we have G, we can find the original number of boys (B) by substituting it into the first equation.
By solving these equations, we can find the original number of boys and girls in the class.