What is the molarity of a solution that contains 2.17 moles of (SrCl2) in 2,660ml of solution?

I know that the formula is molarity=moles/liters
Liters=.2660

mol/L=M

2.17/2.66=M
M=0.8157
also stop cheating lol

To find the molarity of a solution, you need to divide the number of moles of the solute by the volume of the solution in liters.

In this case, you are given that there are 2.17 moles of (SrCl2) and the volume of the solution is 2,660 ml. However, the molarity formula requires the volume to be in liters, so you need to convert the volume from milliliters to liters.

To convert milliliters to liters, divide the volume by 1000 since there are 1000 milliliters in a liter. So, 2660 ml ÷ 1000 = 2.660 liters.

Now you can use the molarity formula: molarity = moles / liters.

Plug in the values: molarity = 2.17 moles / 2.660 liters = 0.816 M.

Therefore, the molarity of the solution is 0.816 M.

If you know the definition is M = mols/L, then what is the problem. Substitute the numbers and out comes the M. By the way, if mL is 2,660 mL, then L = 2.660 L.

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