mg +2Hcl --MgCl2. + h2
Calculate minimum volume of 0.1ml\L
Please help
To calculate the minimum volume of a 0.1M HCl solution required to react completely with a certain amount of magnesium (Mg), you need to use the balanced equation for the reaction and the stoichiometry of the reaction.
The balanced chemical equation is:
Mg + 2HCl -> MgCl2 + H2
From the equation, we can see that:
- 1 mole of magnesium (Mg) reacts with 2 moles of hydrochloric acid (HCl)
- This reaction produces 1 mole of magnesium chloride (MgCl2) and 1 mole of hydrogen gas (H2)
In order to calculate the volume of the HCl solution, we need to follow these steps:
Step 1: Determine the moles of magnesium (Mg):
You need to know the amount of magnesium in moles. If you have the mass of magnesium, you can convert it to moles using its molar mass. The molar mass of magnesium (Mg) is 24.31 g/mol.
Step 2: Determine the moles of HCl required:
Using the stoichiometry of the balanced equation, we know that 1 mole of magnesium (Mg) reacts with 2 moles of HCl. So, the number of moles of HCl required will be twice the moles of magnesium.
Step 3: Calculate the volume of the HCl solution:
Finally, we can calculate the volume of the HCl solution using the molar concentration (Molarity) and the moles of HCl required.
The formula to calculate volume (V) is:
V = (moles of HCl required) / (molar concentration of HCl)
In this case, the molar concentration of the HCl solution is given as 0.1M (0.1 moles/L).
Therefore, you can substitute the values in the formula and calculate the minimum volume of the 0.1M HCl solution required to react completely with the given amount of magnesium.