What is the velocity of the truck after an elastic collision with a car that has a mass of 1.1 × 10^3 kilograms and an initial velocity of +22.0 meters/second, if the car's velocity becomes -11.0 meters/second after the collision?

To solve this problem, we can use the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision. The equation for momentum is given by:

momentum = mass * velocity

Let's assume the mass of the truck is M and its velocity after the collision is V.

Before the collision, the combined momentum of the car and the truck is given by:

momentum_before = (mass of car * velocity of car) + (mass of truck * velocity of truck)

momentum_before = (1.1 × 10^3 kg * 22.0 m/s) + (M * 0 m/s) [since the truck is initially at rest]

After the collision, the combined momentum of the car and the truck is given by:

momentum_after = (mass of car * velocity of car) + (mass of truck * velocity of truck)

momentum_after = (1.1 × 10^3 kg * -11.0 m/s) + (M * V)

According to the law of conservation of momentum, the momentum before the collision is equal to the momentum after the collision:

momentum_before = momentum_after

(1.1 × 10^3 kg * 22.0 m/s) + (M * 0 m/s) = (1.1 × 10^3 kg * -11.0 m/s) + (M * V)

Now, we can solve this equation for the velocity of the truck after the collision (V):

(1.1 × 10^3 kg * 22.0 m/s) = (1.1 × 10^3 kg * -11.0 m/s) + (M * V)

(1.1 × 10^3 kg * 22.0 m/s) - (1.1 × 10^3 kg * -11.0 m/s) = M * V

(1.1 × 10^3 kg * (22.0 m/s + 11.0 m/s)) = M * V

(1.1 × 10^3 kg * 33.0 m/s) = M * V

Divide both sides of the equation by M to solve for V:

V = (1.1 × 10^3 kg * 33.0 m/s) / M

Unfortunately, without the mass of the truck, we cannot determine the exact velocity of the truck after the collision.