Calculate the molarity (M) of 156.2g of H2SO4 in 1.275L of solution.
mols H2SO4 = grams/molar mass = ?
M H2SO4 = mols H2SO4/L solution.
To calculate the molarity (M) of a solution, you need to use the formula:
Molarity (M) = (Amount of solute in grams) / (Volume of solution in liters)
Given:
Amount of H2SO4 = 156.2 grams
Volume of solution = 1.275 liters
Molarity (M) = (156.2 g) / (1.275 L)
Now, we can calculate the molarity:
Molarity (M) = 122.43 M
Therefore, the molarity of the solution is 122.43 M.
To calculate the molarity (M) of a solution, you need to use the formula:
Molarity (M) = number of moles (n) / volume of solution (V)
First, let's calculate the number of moles of H2SO4 using its molar mass. The molar mass of H2SO4 can be calculated as follows:
2(2.016 g/mol) + 1(32.07 g/mol) + 4(16.00 g/mol) = 98.09 g/mol
So, the molar mass of H2SO4 is 98.09 g/mol.
To calculate the number of moles, divide the mass of H2SO4 by its molar mass:
n = mass / molar mass
= 156.2 g / 98.09 g/mol
≈ 1.59 mol
Next, we need to convert the volume of the solution from liters to moles:
V = 1.275 L
Now, we can substitute the values into the formula to find the molarity:
Molarity = n / V
= 1.59 mol / 1.275 L
≈ 1.25 M
Therefore, the molarity of the solution is approximately 1.25 M.