Three blocks of mass 10kg, 20kg, 15kg respectively are being pushed in a row on along a horizontal surface with constant velocity by a force applied to the 10kg block.The coefficient of kinetic friction between each of the blocks and the surface is 0.18.
What is the magnitude of the force applied on the first block(10kg block)?
What is the magnitude of the force that the middle (20kg) block exerts on the 15kg block.
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To find the magnitude of the force applied on the first block (10kg block), we need to consider the forces acting on the system.
1. The applied force on the 10kg block: Let's call this force F_applied.
2. The frictional force between the 10kg block and the surface: The magnitude of the frictional force can be calculated using the equation F_friction = μ * N, where μ is the coefficient of kinetic friction and N is the normal force acting on the block. In this case, since the block is on a horizontal surface and there is no vertical acceleration, the normal force equals the weight of the block, which is equal to mg. Hence, the magnitude of the frictional force acting on the 10kg block is F_friction1 = μ * (mass1 * gravitational acceleration), where mass1 is the mass of the 10kg block.
3. The force exerted by the 10kg block on the 20kg block: Let's call this force F_10kg-20kg.
4. The force exerted by the 20kg block on the 15kg block: Let's call this force F_20kg-15kg.
Since the blocks are moving at a constant velocity, the net force acting on each block must be zero. Therefore, the force applied on the first block (10kg block) must balance the sum of the frictional force acting on the first block and the force exerted on the second block.
Considering the motion of the blocks:
For the first block (10kg block):
F_applied - F_friction1 - F_10kg-20kg = 0
For the second block (20kg block):
F_10kg-20kg - F_friction2 - F_20kg-15kg = 0
Solving these equations simultaneously will allow us to find the magnitudes of the forces.
Now, let's calculate the magnitudes of the forces:
1. The magnitude of the force applied on the first block (10kg block):
F_applied = F_friction1 + F_10kg-20kg
Plug in the given mass (mass1 = 10kg) and the coefficient of kinetic friction (μ = 0.18) into the equation F_friction1 = μ * (mass1 * gravitational acceleration). We also need to calculate the force exerted by the 10kg block on the 20kg block (F_10kg-20kg).
2. The magnitude of the force that the middle (20kg) block exerts on the 15kg block:
We need to calculate the force exerted by the 10kg block on the 20kg block (F_10kg-20kg) and the frictional force between the 20kg block and the surface (F_friction2). Then, the force exerted by the 20kg block on the 15kg block (F_20kg-15kg) can be calculated as F_20kg-15kg = F_10kg-20kg - F_friction2.
Plug in the given masses (mass1 = 10kg, mass2 = 20kg, mass3 = 15kg) and the coefficient of kinetic friction (μ = 0.18) into the equations mentioned above to calculate the magnitudes of the forces F_applied, F_friction1, F_10kg-20kg, F_friction2, and F_20kg-15kg.