Create an image that visually represents a physics problem. Specifically, the scene should contain a cube-shaped oil tank with dimensions of 3m in length, width, and 2m in height. The tank should be filled to the brim with shimmering coconut oil to depict it is full. The oil has a specific gravity of 0.90, which doesn't need to be visually represented. The overall scene should have a clear downward force indication at the bottom of the tank, symbolized by a series of arrows pointing downwards. The image should not contain any text.

An oil tank is 3m long, 3 m wide and 2 m high, when it is full of coconut oil specific gravity of 0.90, find the downward force at the bottom of the tank.

The downward force at the bottom of the tank when it is full of coconut oil with a specific gravity of 0.90 is 16200 kg or 158760 N.

Given:

OIl
Sp G= 0.9
Dimension
3m x 3m and H= 2 m P=2mx 900kg/m^3 x 9.8m/sec^2
F= P x A P = 1800kg/m^3 x 9.8 m/sec^2
but: kg-m/sec^2 is Newton
P=Hdg P =17640 N/m^2
Area= Assume rectangular Tank P=17640 N/m^2 x9m^2
Area= 3x 3= 9^2 P=17640 x 9
F = 158760 N then divide by 9.8 = 16200 kg

Well, I'm glad you asked that, because I’m the expert on all things coconut-related! Now, we have a tank full of coconut oil, and we need to find the downward force at the bottom.

To find the downward force, we need to multiply the volume of the coconut oil by its density times the acceleration due to gravity. Here’s the math:

First, let’s calculate the volume of the tank. The volume of a rectangular prism (which is what our tank is) is given by the formula: volume = length × width × height.

So, in this case, the volume of the tank is: 3m × 3m × 2m = 18 cubic meters.

Now, let's find the mass of the coconut oil. Since we know the specific gravity is 0.90, we can use the formula: density = specific gravity × density of water. The density of water is about 1000 kg/m³.

So, the density of the coconut oil is: 0.90 × 1000 kg/m³ = 900 kg/m³.

Finally, to find the downward force, we multiply the volume by the density and then by the acceleration due to gravity (approximately 9.8 m/s²).

So, the downward force is: 18 m³ × 900 kg/m³ × 9.8 m/s² = 158,760 N.

So, the downward force at the bottom of the tank is approximately 158,760 Newtons. That's a lot of force, but don't worry, the coconut oil can handle it!

To find the downward force at the bottom of the tank, we need to calculate the weight of the coconut oil in the tank.

Here's the step-by-step explanation of how to calculate the downward force:

1. Calculate the volume of the oil in the tank:
The volume of a rectangular tank is given by the formula:
Volume = length × width × height

Given:
Length = 3 m
Width = 3 m
Height = 2 m

Volume = 3 m × 3 m × 2 m
= 18 cubic meters

2. Calculate the mass of the oil:
Mass = Volume × density

The density of coconut oil (specific gravity) is given as 0.90 times the density of water.
Since the density of water is 1000 kg/m³, the density of coconut oil will be:
Density of coconut oil = Specific gravity × Density of water
= 0.90 × 1000 kg/m³
= 900 kg/m³

Mass = Volume × Density
= 18 m³ × 900 kg/m³
= 16200 kg

3. Calculate the weight of the oil:
Weight = Mass × gravitational acceleration

The standard gravitational acceleration is approximately 9.8 m/s².

Weight = Mass × 9.8 m/s²
= 16200 kg × 9.8 m/s²
= 158760 N (Newtons)

Therefore, the downward force at the bottom of the tank when it is full of coconut oil is 158760 Newtons.

mass of oil=density*volume=.90g/ml*18m^3

= .90kg/m^3\ * 18m^3

Weight of oil= above massoil* 9.8N/kg