Find the integral of x/cos^2(x^2)dx
The answer is 1/2 tan (x^2) + C.
Where does the 1/2 come from?
If you let u = x^2, then du = 2x dx
But you only have x dx, which is 1/2 du
The answer is 1/2 tan (x^2) + C.
Where does the 1/2 come from?
But you only have x dx, which is 1/2 du