I have 59.73 grams of a solid dissolved into water. The total is now 115ML of water. I added the water into a beaker already containing said solid. I did not measure how much water I put into the beaker.
59.73g/115ML=0.51g/ML
My question is. Is this the correct way to mix and measure and is my final result of (0.51g/ML) correct? Or did I mess up by not knowing the amount of water I added.
you have the correct m/v density for the solution. I don't know what you were asked to do.
Thank you. It was more of a answer confirmation for my own knowledge!
Based on the information you provided, it seems that you dissolved 59.73 grams of a solid into an unknown amount of water. However, you then measured the total volume of the solution as 115 mL.
To determine the concentration of the solution, you correctly divided the mass of the solid (59.73 g) by the total volume of the solution (115 mL).
So, the calculation you performed is correct:
59.73 g / 115 mL = 0.51 g/mL.
This means that, on average, there is 0.51 grams of the solid dissolved in every milliliter of the solution.
However, since you do not know the actual amount of water you added into the beaker, it might be problematic when it comes to replicating the experiment precisely or comparing results with other experiments. In scientific experiments, it is important to record and control all variables, including the volumes of liquids added.
To improve your experimental procedure, it is recommended to measure the volumes of liquids accurately in order to have precise and reproducible results.