Calculate the number of moles of each of the ions in the following solution:
30.8 mL of 0.507 M AlCl3
Al: .038*.507 moles
Cl: three times the above.
0.038 should be 0.0308.
thanks.
To calculate the number of moles of each ion in the AlCl3 solution, we need to first find the number of moles of AlCl3, and then use the stoichiometry of the compound to determine the number of moles of each ion.
1. Calculate the number of moles of AlCl3:
To find the number of moles, we can use the formula:
Moles = (concentration in M) * (volume in L)
Given:
Concentration (AlCl3) = 0.507 M
Volume (AlCl3) = 30.8 mL = 30.8 / 1000 L (convert mL to L)
Moles (AlCl3) = (0.507 M) * (30.8 / 1000 L) = 0.0156956 moles
2. Determine the number of moles of each ion:
The chemical formula of AlCl3 shows that one Al ion is combined with three Cl ions in a 1:3 ratio.
Therefore, for every 1 mole of AlCl3, we have 1 mole of Al ions and 3 moles of Cl ions.
Moles (Al ions) = (Moles of AlCl3) * (1 Al ion / 1 AlCl3) = 0.0156956 moles
Moles (Cl ions) = (Moles of AlCl3) * (3 Cl ions / 1 AlCl3) = 0.0156956 moles * 3 = 0.0470868 moles
Therefore, the number of moles of Al ions is 0.0156 moles, and the number of moles of Cl ions is 0.0471 moles in the given solution of 30.8 mL of 0.507 M AlCl3.