A marble is flicked horizontally off a desk with a speed of 3.1 m/s. If it takes the marble 0.8 seconds to hit the ground, how far from the desk does it land?
2.48
consider the fall: it fell for .8 seconds.
consider the distance: velocity*time=3.1*.8 meters
To find how far from the desk the marble lands, we can use the formula for horizontal distance traveled by an object in projectile motion:
π = π£π₯ Γ π‘
Where:
π is the horizontal distance traveled,
π£π₯ is the horizontal component of the initial velocity, and
π‘ is the time taken.
In this case, the initial horizontal component of the velocity (π£π₯) is equal to the speed at which the marble was flicked off (3.1 m/s), and the time taken (π‘) is 0.8 seconds.
Substituting the given values into the equation gives us:
π = 3.1 m/s Γ 0.8 s
Calculating this, we get:
π β 2.48 meters
Therefore, the marble lands approximately 2.48 meters away from the desk.