3 kids ages =60
if they are consecutive even integers hat are their ages
60 / 3 = 20
18 + 20 + 22 = 60
another way.
ages: n, n+2, n+4
add them
3n+6=60
3n=54
n=18
n+2=20
n+4=22
To find the ages of the three kids, we can use algebra. Let's assume the ages of the kids are x, x+2, and x+4, where x represents the age of the youngest kid.
According to the given information, the sum of their ages is 60. So we can write an equation:
x + (x+2) + (x+4) = 60
We simplify the equation:
3x + 6 = 60
Next, we'll solve for x:
3x = 60 - 6
3x = 54
x = 54 / 3
x = 18
Now that we know x is 18, we can find the ages of the three kids:
The youngest kid is x = 18
The middle kid is x+2 = 18 + 2 = 20
The oldest kid is x+4 = 18 + 4 = 22
Therefore, if the ages of the three kids are consecutive even integers, their ages are 18, 20, and 22.