3 kids ages =60

if they are consecutive even integers hat are their ages

60 / 3 = 20

18 + 20 + 22 = 60

another way.

ages: n, n+2, n+4

add them
3n+6=60
3n=54
n=18
n+2=20
n+4=22

To find the ages of the three kids, we can use algebra. Let's assume the ages of the kids are x, x+2, and x+4, where x represents the age of the youngest kid.

According to the given information, the sum of their ages is 60. So we can write an equation:

x + (x+2) + (x+4) = 60

We simplify the equation:

3x + 6 = 60

Next, we'll solve for x:

3x = 60 - 6
3x = 54
x = 54 / 3
x = 18

Now that we know x is 18, we can find the ages of the three kids:

The youngest kid is x = 18
The middle kid is x+2 = 18 + 2 = 20
The oldest kid is x+4 = 18 + 4 = 22

Therefore, if the ages of the three kids are consecutive even integers, their ages are 18, 20, and 22.