H3PO4 is a tribasic acid and one of its salt is NaH2PO4.what volume of 1M NaOH solution should be added to 12g of NaH2PO4 to convert it into Na3PO4?
NaH2PO4 + 2NaOH ==> Na3PO4 + 2H2O
mols NaH2PO4 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols NaH2PO4 to mols NaOH used.
Then M NaOH = mols NaOH/L NaOH. You know mols NaOH and M NaOH, solve for L NaOH. Convert to mL if that is the unit you want.
To calculate the volume of 1M NaOH solution needed to convert NaH2PO4 into Na3PO4, you need to understand the stoichiometry of the reaction.
First, let's write the balanced equation for the reaction between NaH2PO4 and NaOH to form Na3PO4:
NaH2PO4 + NaOH -> Na3PO4 + H2O
From the equation, we can see that one molecule of NaH2PO4 reacts with one molecule of NaOH to produce one molecule of Na3PO4.
Step 1: Convert the 12g of NaH2PO4 to moles. To do this, divide the given mass by the molar mass of NaH2PO4.
Molar mass of NaH2PO4:
Na: 22.99 g/mol x 1 = 22.99 g/mol
H: 1.01 g/mol x 2 = 2.02 g/mol
P: 30.97 g/mol
O: 16.00 g/mol x 4 = 64.00 g/mol
Total molar mass = 22.99 + 2.02 + 2(1.01) + 30.97 + 4(16.00) = 120.03 g/mol
Number of moles = mass / molar mass
Number of moles = 12g / 120.03 g/mol = 0.1 mol
Step 2: Determine the stoichiometric ratio between NaH2PO4 and NaOH. From the balanced equation, the ratio is 1:1.
Step 3: Calculate the number of moles of NaOH required to react with 0.1 mol of NaH2PO4. Since the ratio is 1:1, the number of moles of NaOH will be the same.
Number of moles of NaOH = 0.1 mol
Step 4: Convert the moles of NaOH to the volume of the 1M NaOH solution using the molarity equation:
Molarity = moles / volume
Rearranging the equation:
Volume = moles / molarity
Volume = 0.1 mol / 1 mol/L = 0.1 L
The volume of 1M NaOH solution required to convert 12g of NaH2PO4 into Na3PO4 is 0.1 liters (100 mL).